A sound source
, emitting a sound of frequency 400 Hz and a receiver
of mass m are at the same point. R is performing SHM with the help of a spring offeree constant
. At a time
is at the mean position and moving towards the right, as shown. At the same time, the source starts moving away from
with some acceleration a. The frequency registered by the receiver at a time
is 250 Hz . What is the time (in seconds) at which the corresponding registered frequency of 250 Hz was emitted by the source? [Given that
and amplitude of oscillation 

Text Solution
Verified by ExpertsCHECK THE SOLUTION
(8)
The time period of oscillation
So at
, the receiver passes through mean position towards the right with a speed

Using doppler's formula


So the velocity of the source is
at the time of emission of the wave which was received by the receiver at
Let's say the time instant when the wave was emitted is
, then the distance of the source from the receiver is
at
. This distance is travelled by the wave in a time
. So,

Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems